Mapping by Name
+If your property names don't match your class names, you can map the property to the column by name.
+Data
+ColumnA,ColumnB
+1,one
+
+Example
+void Main()
+{
+ using (var reader = new StreamReader("path\\to\\file.csv"))
+ using (var csv = new CsvReader(reader, CultureInfo.InvariantCulture))
+ {
+ csv.Context.RegisterClassMap<FooMap>();
+ var records = csv.GetRecords<Foo>();
+ }
+}
+
+public class Foo
+{
+ public int Id { get; set; }
+ public string Name { get set; }
+}
+
+public sealed class FooMap : ClassMap<Foo>
+{
+ public FooMap()
+ {
+ Map(m => m.Id).Name("ColumnA");
+ Map(m => m.Name).Name("ColumnB");
+ }
+}
+
+
+